Quadratic Equations Comparision Amongst Solution Asked Inwards Sbi Clerk Prelims 2018(23Rd June & 24Th June)

Solved Quadratic Equations Asked inwards SBI Clerk

Dear students, nosotros are sharing reply in addition to detailed explanation of Quadratic Equations(Numerical Ability) Asked inwards SBI Clerk Prelims 2018 Exam held on 23rd June in addition to 24th June.

Quadratic Equations Asked inwards SBI Clerk Prelims 2018(23 June):

Question1) In the next question, in that place are ii equations (I) in addition to (II). Solve the equations in addition to reply accordingly:

Give Answer:

(a)x>y

(b)x<y

(c)x=y or relation can’t survive established betwixt x & y

(d)x≥y

(e)x≤y

I.x² – 5x + half dozen = 0

II.y² – 9y + 20= 0

Answer & Explanation:

Solve I.x² – 5x + half dozen = 0

Or,x² – 5x + half dozen = 0

Or,x² – 3x-2x + half dozen = 0

Or,x(x – 3)-2(x – 3) = 0

Or,(x-2)(x – 3) = 0

X=2 or 3

Solve II.y² – 9y + 20= 0

Or, y² – 5y– 4y + 20= 0

Or,y(y – 5)-4(y – 5) = 0

Or,(y-5)(x – 4) = 0

y=5 or 4

Now, Compare x in addition to y:

2<5 agency x<y

2<4 agency x<y

3<5 agency x<y

3<4 agency x<y

Therefore x<y is the right answer.

Question 2) In the next question, in that place are ii equations (I) in addition to (II). Solve the equations in addition to reply accordingly:

Give Answer:

(a)x>y

(b)x<y

(c)x=y or relation can’t survive established betwixt x & y

(d)x≥y

(e)x≤y

I.6x² – 11x + iv =0

II.50y² – 25y + iii =0

Answer & Explanation:

Solve I.6x² – 11x + iv =0

Or, 6x² – 8x-3x + iv =0

Or, 2x(3x –4) -1(3x – 4) =0

Or, (2x -1)(3x – 4) =0

Or, x=1/2=0.5 or x=4/3=1.33

Solve II.50y² – 25y + iii =0

Or, 50y² – 15y– 10y + iii =0

Or, 5y(10y – 3)– 1(10y – 3) =0

Or, (5y– 1)(10y – 3) =0

Or,y=1/5=0.2 or y=3/10=0.3

Now, Compare x in addition to y:

0.5>0.2 agency x>y

0.5>0.3 agency x>y

1.33>0.2 agency x>y

1.33>0.3 agency x>y

Therefore x>y is the right answer.

Question 3) In the next question, in that place are ii equations (I) in addition to (II). Solve the equations in addition to reply accordingly:

Give Answer:

(a)x>y

(b)x<y

(c)x=y or relation can’t survive established betwixt x & y

(d)x≥y

(e)x≤y

I.x² – 4x – 12 =0

II.y² – 5y – xiv =0

Answer & Explanation:

Solve I.x² – 4x – 12 =0

Or, x² – 6x+ 2x – 12 =0

Or, x(x – 6) + 2(x – 6) =0

Or, (x + 2)(x – 6) =0

Or,x=-2 or 6

Solve II.y² – 5y – xiv =0

Or, y² – 7y+ 2y – xiv =0

Or, y(y – 7)+ 2(y –7) =0

Or, (y+ 2)(y –7) =0

Or,y=-2 or 7

Now, Compare x in addition to y:

-2>-2 agency x=y

-2<7 agency x<y

6>-2 agency x>y

6<7 agency x<y

Therefore No human relationship tin dismiss survive established because >,< & = never happen together.

Question 4) In the next question, in that place are ii equations (I) in addition to (II). Solve the equations in addition to reply accordingly:

Give Answer:

(a)x>y

(b)x<y

(c)x=y or relation can’t survive established betwixt x & y

(d)x≥y

(e)x≤y

I.3x² + 8x + 4=0

II.6y² + 7y + 2 =0

Answer & Explanation:

Solve I.3x² + 8x + 4=0

Or, 3x² + 6x+ 2x + 4=0

Or, 3x(x + 2) + 2(x + 2)=0

Or, (3x + 2) + (x + 2)=0

Or, x=-2/3=-0.66 or x=-2

Solve II.6y² + 7y + 2 =0

Or, 6y² + 4y + 3y + 2 =0

Or, 2y(3y + 2) +1( 3y + 2) =0

Or, (2y+1)( 3y + 2) =0

Or,y=-1/2=-0.5 or y=-2/3=-0.66

Now, Compare x in addition to y:

-0.66>-0.5 agency x<y

-0.66=-0.66 agency x=y

-2>-0.5 agency x<y

-2<-0.66 agency x<y

Therefore x≤y  is the right answer.

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